8m+m^2=12

Solution for 8m+m^2=12 equation:

8m+m^2=12

We move all terms to the left:

8m+m^2-(12)=0

a = 1; b = 8; c = -12;
Δ = b2-4ac
Δ = 82-4·1·(-12)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{7}}{2*1}=\frac{-8-4\sqrt{7}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{7}}{2*1}=\frac{-8+4\sqrt{7}}{2}
$